Function removeAllOf

removeAllOf<T>(array, value, start?, stop?): number
Remove all occurrences of a value from an array.
Type Parameters
- T
Parameters
- array: T[]
  The array of interest.
- value: T
  The value to remove from the array. Values are compared using strict === equality.
- start: number = 0
  The index of the first element in the range to be searched, inclusive. The default value is 0. Negative values are taken as an offset from the end of the array.
- stop: number = -1
  The index of the last element in the range to be searched, inclusive. The default value is -1. Negative values are taken as an offset from the end of the array.
Returns number
The number of elements removed from the array.

Notes
If stop < start the search will conceptually wrap at the end of the array, however the array will be traversed front-to-back.

Complexity
Linear.

Example
```
import { ArrayExt } from '@lumino/algorithm';

let data = [14, 12, 23, 39, 14, 12, 19, 14];
ArrayExt.removeAllOf(data, 12);        // 2
ArrayExt.removeAllOf(data, 17);        // 0
ArrayExt.removeAllOf(data, 14, 1, 4);  // 1
```
- Defined in array.ts:1270